7^(3x+1)=(1/49)^(1-x)

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Solution for 7^(3x+1)=(1/49)^(1-x) equation: 



7^(3x+1)=(1/49)^(1-x)

We move all terms to the left:

7^(3x+1)-((1/49)^(1-x))=0



Domain of the equation: 49)^(1-x))!=0

x∈R



We add all the numbers together, and all the variables

7^(3x+1)-((+1/49)^(-1x+1))=0

We multiply all the terms by the denominator


(7^(3x+1))*49)^(-1x+1+1))-((=0

We add all the numbers together, and all the variables

(7^(3x+1))*49)^(-1x+2))-((=0

We add all the numbers together, and all the variables

-1x+(7^(3x+1))*49)^(=0

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